# 58-I.翻转单词顺序

### 一、 题目

输入一个英文句子，翻转句子中单词的顺序，但单词内字符的顺序不变。为简单起见，标点符号和普通字母一样处理。例如输入字符串"I am a student. "，则输出"student. a am I"。

 

示例 1：

输入: "the sky is blue"

输出: "blue is sky the"

示例 2：

输入: "  hello world!  "

输出: "world! hello"

解释: 输入字符串可以在前面或者后面包含多余的空格，但是反转后的字符不能包括。

示例 3：

输入: "a good   example"

输出: "example good a"

解释: 如果两个单词间有多余的空格，将反转后单词间的空格减少到只含一个。

说明：

无空格字符构成一个单词。

输入字符串可以在前面或者后面包含多余的空格，但是反转后的字符不能包括。

如果两个单词间有多余的空格，将反转后单词间的空格减少到只含一个。

来源：力扣（LeetCode）

链接：<https://leetcode-cn.com/problems/fan-zhuan-dan-ci-shun-xu-lcof>

著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

### 二、 解法

```
func reverseWords(_ s: String) -> String {
    var res: String = ""
    var temp: String = ""
    
    for i in s {
        if i == " " {
            if temp.isEmpty == false {
                res = (res.isEmpty == false) ? "\(temp) \(res)" : temp
                temp = ""
            }
        }
        else {
            temp = "\(temp)\(i)"
        }
    }
    
    if temp.isEmpty == false {
        res = (res.isEmpty == false) ? "\(temp) \(res)" : temp
    }
    
    return res
}
```


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